PhysicsEasy145×since 2002Q6647Let K₁ and K₂ be the maximum kinetic energies of photo-electrons emitted when two monochromatic beams of wavelength λ\lambdaλ₁ and λ\lambdaλ₂, respectively are incident on a metallic surface. If λ\lambdaλ₁ = 3λ\lambdaλ₂ then :AK1>K23{K_1} > {{{K_2}} \over 3}K1>3K2BK1<K23{K_1} < {{{K_2}} \over 3}K1<3K2CK1=K23{K_1} = {{{K_2}} \over 3}K1=3K2DK2=K13{K_2} = {{{K_1}} \over 3}K2=3K1Check answerSkip