MathematicsMedium210×since 2002Q3404Let g(x) = ∫0xf(t)dt\int_0^x {f(t)dt}∫0xf(t)dt, where f is continuous function in [ 0, 3 ] such that 13{1 \over 3}31 ≤\le≤ f(t) ≤\le≤ 1 for all t∈\in∈ [0, 1] and 0 ≤\le≤ f(t) ≤\le≤ 12{1 \over 2}21 for all t∈\in∈ (1, 3]. The largest possible interval in which g(3) lies is :A[−1,−12]\left[ { - 1, - {1 \over 2}} \right][−1,−21]B[−32,−1]\left[ { - {3 \over 2}, - 1} \right][−23,−1]C[1, 3]D[13,2]\left[ {{1 \over 3},2} \right][31,2]Check answerSkip