MathematicsHard94×since 2002Q2879Let g(x) = cosx², f(x) = x\sqrt xx and α,β(α<β)\alpha ,\beta \left( {\alpha < \beta } \right)α,β(α<β) be the roots of the quadratic equation 18x² - 9π\piπx + π2{\pi ^2}π2 = 0. Then the area (in sq. units) bounded by the curve y = (gof)(x) and the lines x=αx = \alphax=α, x=βx = \betax=β and y = 0 is :A12(2−1){1 \over 2}\left( {\sqrt 2 - 1} \right)21(2−1)B12(3−1){1 \over 2}\left( {\sqrt 3 - 1} \right)21(3−1)C12(3+1){1 \over 2}\left( {\sqrt 3 + 1} \right)21(3+1)D12(3−2){1 \over 2}\left( {\sqrt 3 - \sqrt 2 } \right)21(3−2)Check answerSkip