MathematicsMedium244×since 2002Q4544Let for A = \left[ {\matrix{ 1 & 2 & 3 \cr \alpha & 3 & 1 \cr 1 & 1 & 2 \cr } } \right],|A| = 2. If ∣2 adj (2 adj (2A))∣=32n\mathrm{|2\,adj\,(2\,adj\,(2A))| = {32^n}}∣2adj(2adj(2A))∣=32n, then 3n+α3n + \alpha3n+α is equal toA11B9C12D10Check answerSkip