MathematicsHard110×since 2002Q3826Let f(x)=x−1x+1, x∈R−{0,−1,1}f(x) = {{x - 1} \over {x + 1}},\,x \in R - \{ 0, - 1,1\}f(x)=x+1x−1,x∈R−{0,−1,1}. If fn+1(x)=f(fn(x)){f^{n + 1}}(x) = f({f^n}(x))fn+1(x)=f(fn(x)) for all n ∈\in∈ N, then f6(6)+f7(7){f^6}(6) + {f^7}(7)f6(6)+f7(7) is equal to :A76{7 \over 6}67B−32- {3 \over 2}−23C712{7 \over {12}}127D−1112- {{11} \over {12}}−1211Check answerSkip