MathematicsMedium179×since 2002Q4231Let f(x) = 5 – |x – 2| and g(x) = |x + 1|, x ∈\in∈ R. If f(x) attains maximum value at α\alphaα and g(x) attains minimum value at β\betaβ, then limx→−αβ(x−1)(x2−5x+6)x2−6x+8\mathop {\lim }\limits_{x \to -\alpha \beta } {{\left( {x - 1} \right)\left( {{x^2} - 5x + 6} \right)} \over {{x^2} - 6x + 8}}x→−αβlimx2−6x+8(x−1)(x2−5x+6) is equal to :A12{1 \over 2}21B−12-{1 \over 2}−21C32{3 \over 2}23D−32-{3 \over 2}−23Check answerSkip