Let f : S … S where S = (0, …) be a twice differentiable function such that f(x + 1) = xf(x). If g : S … R be defined as g(x) = log_e f(x), then the value of |g''(5) … g''(1)| is equal to :

Limits Continuity and Differentiability

JEE Main 2021 · 16 Mar, Evening shift · Q4201

MathematicsMedium179×since 2002Q4201

Let f : S

\to

S where S = (0,

\infty

) be a twice differentiable function such that f(x + 1) = xf(x). If g : S

\to

R be defined as g(x) = log_e f(x), then the value of |g''(5)

-

g''(1)| is equal to :