MathematicsMedium110×since 2002Q3827Let f : R →\to→ R be defined as f (x) = x −-− 1 and g : R −-− {1, −-−1} →\to→ R be defined as g(x)=x2x2−1g(x) = {{{x^2}} \over {{x^2} - 1}}g(x)=x2−1x2. Then the function fog is :Aone-one but not ontoBonto but not one-oneCboth one-one and ontoDneither one-one nor ontoCheck answerSkip