MathematicsMedium179×since 2002Q4236Let f : R →\to→ R be a function such that f(2) = 4 and f'(2) = 1. Then, the value of limx→2x2f(2)−4f(x)x−2\mathop {\lim }\limits_{x \to 2} {{{x^2}f(2) - 4f(x)} \over {x - 2}}x→2limx−2x2f(2)−4f(x) is equal to :A4B8C16D12Check answerSkip