MathematicsMedium210×since 2002Q3478Let f:[−π2,π2]→Rf:\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \rightarrow \mathbf{R}f:[−2π,2π]→R be a differentiable function such that f(0)=12f(0)=\frac{1}{2}f(0)=21. If the \lim _\limits{x \rightarrow 0} \frac{x \int_0^x f(\mathrm{t}) \mathrm{dt}}{\mathrm{e}^{x^2}-1}=\alpha, then 8α28 \alpha^28α2 is equal to :A4B2C1D16Check answerSkip