MathematicsMedium75×since 2002Q4944Let E and F be two independent events. The probability that both E and F happen is 112{1 \over {12}}121 and the probability that neither E nor F happens is 12{1 \over {2}}21, then a value of P(E)P(F){{P\left( E \right)} \over {P\left( F \right)}}P(F)P(E) is :A43{4 \over 3}34B32{3 \over 2}23C13{1 \over 3}31D512{5 \over 12}125Check answerSkip