MathematicsMedium38×since 2002Q3648Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x2+4)2dy+(2x3y+8xy−2)dx=0(x^2+4)^2 d y+(2 x^3 y+8 x y-2) d x=0(x2+4)2dy+(2x3y+8xy−2)dx=0. If y(0)=0y(0)=0y(0)=0, then y(2)y(2)y(2) is equal toA2π2 \pi2πBπ8\frac{\pi}{8}8πCπ16\frac{\pi}{16}16πDπ32\frac{\pi}{32}32πCheck answerSkip