MathematicsMedium38×since 2002Q3649Let y=y(x)y=y(x)y=y(x) be the solution curve of the differential equation secydy dx+2xsiny=x3cosy,y(1)=0\sec y \frac{\mathrm{d} y}{\mathrm{~d} x}+2 x \sin y=x^3 \cos y, y(1)=0secy dxdy+2xsiny=x3cosy,y(1)=0. Then y(3)y(\sqrt{3})y(3) is equal to:Aπ6\frac{\pi}{6}6πBπ12\frac{\pi}{12}12πCπ3\frac{\pi}{3}3πDπ4\frac{\pi}{4}4πCheck answerSkip