MathematicsMedium249×since 2002Q2531Let (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) be the foot of perpendicular from the point (1,2,3)(1,2,3)(1,2,3) on the line x+35=y−12=z+43\frac{x+3}{5}=\frac{y-1}{2}=\frac{z+4}{3}5x+3=2y−1=3z+4. Then 19(α+β+γ)19(\alpha+\beta+\gamma)19(α+β+γ) is equal to :A99B102C101D100Check answerSkip