MathematicsHard128×since 2002Q5546Let C(α,β)C(\alpha, \beta)C(α,β) be the circumcenter of the triangle formed by the lines 4x+3y=694 x+3 y=694x+3y=69 4y−3x=174 y-3 x=174y−3x=17, and x+7y=61x+7 y=61x+7y=61. Then (α−β)2+α+β(\alpha-\beta)^{2}+\alpha+\beta(α−β)2+α+β is equal to :A15B17C16D18Check answerSkip