MathematicsEasy249×since 2002Q2529Let PQRP Q RPQR be a triangle with R(−1,4,2)R(-1,4,2)R(−1,4,2). Suppose M(2,1,2)M(2,1,2)M(2,1,2) is the mid point of PQ\mathrm{PQ}PQ. The distance of the centroid of △PQR\triangle \mathrm{PQR}△PQR from the point of intersection of the lines x−20=y2=z+3−1\frac{x-2}{0}=\frac{y}{2}=\frac{z+3}{-1}0x−2=2y=−1z+3 and x−11=y+3−3=z+11\frac{x-1}{1}=\frac{y+3}{-3}=\frac{z+1}{1}1x−1=−3y+3=1z+1 isA69B99\sqrt{99}99C69\sqrt{69}69D9Check answerSkip