MathematicsMedium175×since 2002Q2789Let λx−2y=μ\lambda x - 2y = \muλx−2y=μ be a tangent to the hyperbola a2x2−y2=b2{a^2}{x^2} - {y^2} = {b^2}a2x2−y2=b2. Then (λa)2−(μb)2{\left( {{\lambda \over a}} \right)^2} - {\left( {{\mu \over b}} \right)^2}(aλ)2−(bμ)2 is equal to :A−-−2B−-−4C2D4Check answerSkip