MathematicsHard178×since 2002Q5342Let <an>< a_{\mathrm{n}} ><an> be a sequence such that a1+a2+…+an=n2+3n(n+1)(n+2)a_{1}+a_{2}+\ldots+a_{n}=\frac{n^{2}+3 n}{(n+1)(n+2)}a1+a2+…+an=(n+1)(n+2)n2+3n. If 28 \sum_\limits{k=1}^{10} \frac{1}{a_{k}}=p_{1} p_{2} p_{3} \ldots p_{m}, where p1,p2,….,pm\mathrm{p}_{1}, \mathrm{p}_{2}, \ldots ., \mathrm{p}_{\mathrm{m}}p1,p2,….,pm are the first m\mathrm{m}m prime numbers, then m\mathrm{m}m is equal toA5B7C6D8Check answerSkip