MathematicsMedium94×since 2002Q2878Let f(x)f(x)f(x) be a non - negative continuous function such that the area bounded by the curve y=f(x),y=f(x),y=f(x), xxx-axis and the ordinates x=π4x = {\pi \over 4}x=4π and x=β>π4x = \beta > {\pi \over 4}x=β>4π is (βsinβ+π4cosβ+2β).\left( {\beta \sin \beta + {\pi \over 4}\cos \beta + \sqrt 2 \beta } \right).(βsinβ+4πcosβ+2β). Then f(π2)f\left( {{\pi \over 2}} \right)f(2π) isA(π4+2−1)\left( {{\pi \over 4} + \sqrt 2 - 1} \right)(4π+2−1)B(π4−2+1)\left( {{\pi \over 4} - \sqrt 2 + 1} \right)(4π−2+1)C(1−π4−2)\left( {1 - {\pi \over 4} - \sqrt 2 } \right)(1−4π−2)D(1−π4+2)\left( {1 - {\pi \over 4} + \sqrt 2 } \right)(1−4π+2)Check answerSkip