MathematicsMedium210×since 2002Q3300Let f:R→Rf:R \to Rf:R→R be a differentiable function having f(2)=6f\left( 2 \right) = 6f(2)=6, f′(2)=(148)f'\left( 2 \right) = \left( {{1 \over {48}}} \right)f′(2)=(481). Then limx→2∫6f(x)4t3x−2dt\mathop {\lim }\limits_{x \to 2} \int\limits_6^{f\left( x \right)} {{{4{t^3}} \over {x - 2}}dt}x→2lim6∫f(x)x−24t3dt equals :A242424B363636C121212D181818Check answerSkip