MathematicsMedium210×since 2002Q3319Let fff be a continuous function satisfying \int_\limits{0}^{t^{2}}\left(f(x)+x^{2}\right) d x=\frac{4}{3} t^{3}, \forall t > 0. Then f(π24)f\left(\frac{\pi^{2}}{4}\right)f(4π2) is equal to :A−π(1+π316)-\pi\left(1+\frac{\pi^{3}}{16}\right)−π(1+16π3)Bπ(1−π316)\pi\left(1-\frac{\pi^{3}}{16}\right)π(1−16π3)C−π2(1+π216)-\pi^{2}\left(1+\frac{\pi^{2}}{16}\right)−π2(1+16π2)Dπ2(1−π216)\pi^{2}\left(1-\frac{\pi^{2}}{16}\right)π2(1−16π2)Check answerSkip