MathematicsMedium53×since 2002Q3171Let zzz be a complex number such that ∣z+2∣=1|z+2|=1∣z+2∣=1 and lm(z+1z+2)=15\operatorname{lm}\left(\frac{z+1}{z+2}\right)=\frac{1}{5}lm(z+2z+1)=51. Then the value of ∣Re(z+2‾)∣|\operatorname{Re}(\overline{z+2})|∣Re(z+2)∣ isA265\frac{2 \sqrt{6}}{5}526B245\frac{24}{5}524C65\frac{\sqrt{6}}{5}56D1+65\frac{1+\sqrt{6}}{5}51+6Check answerSkip