MathematicsMedium128×since 2002Q5555Let A(a,b),B(3,4)A(a, b), B(3,4)A(a,b),B(3,4) and C(−6,−8)C(-6,-8)C(−6,−8) respectively denote the centroid, circumcentre and orthocentre of a triangle. Then, the distance of the point P(2a+3,7b+5)P(2 a+3,7 b+5)P(2a+3,7b+5) from the line 2x+3y−4=02 x+3 y-4=02x+3y−4=0 measured parallel to the line x−2y−1=0x-2 y-1=0x−2y−1=0 isA1756\frac{17 \sqrt{5}}{6}6175B1557\frac{15 \sqrt{5}}{7}7155C1757\frac{17 \sqrt{5}}{7}7175D517\frac{\sqrt{5}}{17}175Check answerSkip