MathematicsMedium58×since 2004Q5364Let A={2,3,4}\mathrm{A}=\{2,3,4\}A={2,3,4} and B={8,9,12}\mathrm{B}=\{8,9,12\}B={8,9,12}. Then the number of elements in the relation R={((a1, b1),(a2, b2))∈(A×B,A×B):a1\mathrm{R}=\left\{\left(\left(a_{1}, \mathrm{~b}_{1}\right),\left(a_{2}, \mathrm{~b}_{2}\right)\right) \in(A \times B, A \times B): a_{1}\right.R={((a1, b1),(a2, b2))∈(A×B,A×B):a1 divides b2\mathrm{b}_{2}b2 and a2\mathrm{a}_{2}a2 divides b1}\left.\mathrm{b}_{1}\right\}b1} is :A18B24C36D12Check answerSkip