MathematicsMedium128×since 2002Q5572Let A(−1,1)\mathrm{A}(-1,1)A(−1,1) and B(2,3)\mathrm{B}(2,3)B(2,3) be two points and P\mathrm{P}P be a variable point above the line AB\mathrm{AB}AB such that the area of △PAB\triangle \mathrm{PAB}△PAB is 10. If the locus of P\mathrm{P}P is ax+by=15\mathrm{a} x+\mathrm{by}=15ax+by=15, then 5a+2 b5 \mathrm{a}+2 \mathrm{~b}5a+2 b is :A−125-\frac{12}{5}−512B−65-\frac{6}{5}−56C6D4Check answerSkip