MathematicsEasy98×since 2002Q4807Let α=(4!)!(4!)3!\alpha=\frac{(4 !) !}{(4 !)^{3 !}}α=(4!)3!(4!)! and β=(5!)!(5!)4!\beta=\frac{(5 !) !}{(5 !)^{4 !}}β=(5!)4!(5!)!. Then :Aα∈N\alpha \in \mathbf{N}α∈N and β∈N\beta \in \mathbf{N}β∈NBα∈N\alpha \in \mathbf{N}α∈N and β∉N\beta \notin \mathbf{N}β∈/NCα∉N\alpha \notin \mathbf{N}α∈/N and β∈N\beta \in \mathbf{N}β∈NDα∉N\alpha \notin \mathbf{N}α∈/N and β∉N\beta \notin \mathbf{N}β∈/NCheck answerSkip