MathematicsEasy202×since 2002Q5832Let a⃗\vec{a}a and b⃗\vec{b}b be two vectors, Let ∣a⃗∣=1,∣b⃗∣=4|\vec{a}|=1,|\vec{b}|=4∣a∣=1,∣b∣=4 and a⃗⋅b⃗=2\vec{a} \cdot \vec{b}=2a⋅b=2. If c⃗=(2a⃗×b⃗)−3b⃗\vec{c}=(2 \vec{a} \times \vec{b})-3 \vec{b}c=(2a×b)−3b, then the value of b⃗⋅c⃗\vec{b} \cdot \vec{c}b⋅c is :A−48-48−48B−60-60−60C−84-84−84D−24-24−24Check answerSkip