MathematicsHard244×since 2002Q4430Let αβ≠0\alpha \beta \neq 0αβ=0 and A=[βα3ααβ−βα2α]A=\left[\begin{array}{rrr}\beta & \alpha & 3 \\ \alpha & \alpha & \beta \\ -\beta & \alpha & 2 \alpha\end{array}\right]A=βα−βααα3β2α. If B=[3α−93α−α7−2α−2α5−2β]B=\left[\begin{array}{rrr}3 \alpha & -9 & 3 \alpha \\ -\alpha & 7 & -2 \alpha \\ -2 \alpha & 5 & -2 \beta\end{array}\right]B=3α−α−2α−9753α−2α−2β is the matrix of cofactors of the elements of AAA, then det(AB)\operatorname{det}(A B)det(AB) is equal to :A64B343C125D216Check answerSkip