Sequences and Series

JEE Main 2018 · 15 Apr, Evening shift · Q5300

MathematicsHard178×since 2002Q5300

Let A_n =

\left( {{3 \over 4}} \right) - {\left( {{3 \over 4}} \right)^2} + {\left( {{3 \over 4}} \right)^3}

-

. . . . . + (

-

1)^n-1

{\left( {{3 \over 4}} \right)^n}

and B_n = 1

-

A_n. Then, the least dd natural numbr p, so that B_n > A_n , for all n

\ge

p, is :

JEE Main 2018 · 15 Apr, Evening shift · Q5300

MathematicsHard178×since 2002Q5300

Let A_n =

\left( {{3 \over 4}} \right) - {\left( {{3 \over 4}} \right)^2} + {\left( {{3 \over 4}} \right)^3}

-

. . . . . + (

-

1)^n-1

{\left( {{3 \over 4}} \right)^n}

and B_n = 1

-

A_n. Then, the least dd natural numbr p, so that B_n > A_n , for all n

\ge

p, is :

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