MathematicsMedium244×since 2002Q4455Let A = \left[ {\matrix{ 2 & b & 1 \cr b & {{b^2} + 1} & b \cr 1 & b & 2 \cr } } \right] where b > 0. Then the minimum value of det(A)b{{\det \left( A \right)} \over b}bdet(A) is -A3\sqrt 33B−-− 232\sqrt 323C−3- \sqrt 3−3D232\sqrt 323Check answerSkip