MathematicsMedium75×since 2002Q4912Let A denote the event that a 6-digit integer formed by 0, 1, 2, 3, 4, 5, 6 without repetitions, be divisible by 3. Then probability of event A is equal to :A49{4 \over {9}}94B956{9 \over {56}}569C1127{11 \over {27}}2711D37{3 \over {7}}73Check answerSkip