MathematicsMedium128×since 2002Q5513Let A (h,k)\left( {h,k} \right)(h,k), B(1,1)\left( {1,1} \right)(1,1) and C (2,1)(2, 1)(2,1) be the vertices of a right angled triangle with AC as its hypotenuse. If the area of the triangle is 111 square unit, then the set of values which ′k′'k'′k′ can take is given by :A{−1,3}\left\{ { - 1,3} \right\}{−1,3}B{−3,−2}\left\{ { - 3, - 2} \right\}{−3,−2}C{1,3}\left\{ { 1,3} \right\}{1,3}D{0,2}\left\{ {0,2} \right\}{0,2}Check answerSkip