MathematicsMedium75×since 2002Q4955Let A and B be two independent events such that P(A) = 13{1 \over 3}31 and P(B) = 16{1 \over 6}61. Then, which of the following is TRUE?AP(AA∪B)=14P\left( {{A \over {A \cup B}}} \right) = {1 \over 4}P(A∪BA)=41BP(AB)=23P\left( {{A \over B}} \right) = {2 \over 3}P(BA)=32CP(A′B′)=13P\left( {{{A'} \over {B'}}} \right) = {1 \over 3}P(B′A′)=31DP(AB′)=13P\left( {{A \over {B'}}} \right) = {1 \over 3}P(B′A)=31Check answerSkip