MathematicsMedium244×since 2002Q4526Let A(a, 0), B(b, 2b + 1) and C(0, b), b ≠\ne= 0, |b| ≠\ne= 1, be points such that the area of triangle ABC is 1 sq. unit, then the sum of all possible values of a is :A−2bb+1{{ - 2b} \over {b + 1}}b+1−2bB2bb+1{{2b} \over {b + 1}}b+12bC2b2b+1{{2{b^2}} \over {b + 1}}b+12b2D−2b2b+1{{ - 2{b^2}} \over {b + 1}}b+1−2b2Check answerSkip