MathematicsHard178×since 2002Q5196Let a1{a_1}a1, a2{a_2}a2, a3{a_3}a3, ......... ,a49{a_{49}}a49 be in A.P. such that ∑k=012a4k+1=416\sum\limits_{k = 0}^{12} {{a_{4k + 1}}} = 416k=0∑12a4k+1=416 and a9+a43=66{a_9} + {a_{43}} = 66a9+a43=66. a12+a22+.......+a172=140ma_1^2 + a_2^2 + ....... + a_{17}^2 = 140ma12+a22+.......+a172=140m, then m is equal toA33B66C68D34Check answerSkip