MathematicsMedium210×since 2002Q3419∫616logex2logex2+loge(x2−44x+484)dx\int\limits_6^{16} {{{{{\log }_e}{x^2}} \over {{{\log }_e}{x^2} + {{\log }_e}({x^2} - 44x + 484)}}dx}6∫16logex2+loge(x2−44x+484)logex2dx is equal to :A6B8C5D10Check answerSkip