MathematicsMedium210×since 2002Q3458∫324334489−4x2dx\int\limits_{{{3\sqrt 2 } \over 4}}^{{{3\sqrt 3 } \over 4}} {{{48} \over {\sqrt {9 - 4{x^2}} }}dx}432∫4339−4x248dx is equal to :Aπ2{\pi \over 2}2πBπ3{\pi \over 3}3πCπ6{\pi \over 6}6πD2π2\pi2πCheck answerSkip