PhysicsHard226×since 2002Q6478In an ammeter, 5%5 \%5% of the main current passes through the galvanometer. If resistance of the galvanometer is G\mathrm{G}G, the resistance of ammeter will be :A199 G199 \mathrm{~G}199 GB200 G200 \mathrm{~G}200 GCG20\frac{G}{20}20GDG199\frac{\mathrm{G}}{199}199GCheck answerSkip