PhysicsEasy183×since 2002Q6093In a radioactive decay chain, the initial nucleus is 90232{}_{90}^{232}90232Th. At the end there are 6 α\alphaα-particles and 4 β\betaβ-particles which are emitted. If the end nucleus is ZA{}_Z^AZAX, A and Z are given by :AA = 208; Z = 80BA = 208; Z = 82CA = 200; Z = 81DA = 202; Z = 80Check answerSkip