PhysicsMedium183×since 2002Q6066In a hypothetical fission reaction 92X236→56Y141+36Z92+3R{ }_{92} X^{236} \rightarrow{ }_{56} \mathrm{Y}^{141}+{ }_{36} Z^{92}+3 R92X236→56Y141+36Z92+3R The identity of emitted particles (R) is :AProtonBNeutronCElectronDγ\gammaγ-radiationsCheck answerSkip