MathematicsMedium38×since 2002Q3603If y = y(x) is the solution of the differential equation, ey(dydx−1)=ex{e^y}\left( {{{dy} \over {dx}} - 1} \right) = {e^x}ey(dxdy−1)=ex such that y(0) = 0, then y(1) is equal to:A2 + log_e2Blog_e2C1 + log_e2D2eCheck answerSkip