MathematicsMedium38×since 2002Q3527If y = y(x) is the solution of the differential equation, dydx+2ytanx=sinx,y(π3)=0{{dy} \over {dx}} + 2y\tan x = \sin x,y\left( {{\pi \over 3}} \right) = 0dxdy+2ytanx=sinx,y(3π)=0, then the maximum value of the function y(x) over R is equal to:A18{1 \over 8}81B8C−-−154{15 \over 4}415D12{1 \over 2}21Check answerSkip