MathematicsMedium38×since 2002Q3494If y=(2πx−1)cosec xy = \left( {{2 \over \pi }x - 1} \right) cosec\,xy=(π2x−1)cosecx is the solution of the differential equation, dydx+p(x)y=2πcosec x{{dy} \over {dx}} + p\left( x \right)y = {2 \over \pi } cosec\,xdxdy+p(x)y=π2cosecx, 0<x<π20 < x < {\pi \over 2}0<x<2π, then the function p(x) is equal to :Acot xBsec xCtan xDcosec xCheck answerSkip