MathematicsMedium175×since 2002Q2692If 2a+3b+6c=02a+3b+6c=02a+3b+6c=0, then at least one root of the equation ax2+bx+c=0a{x^2} + bx + c = 0ax2+bx+c=0 lies in the intervalA(1,3)(1, 3)(1,3)B(1,2)(1, 2)(1,2)C(2,3)(2, 3)(2,3)D(0,1)(0, 1)(0,1)Check answerSkip