PhysicsEasy183×since 2002Q6025If the wavelength of the first member of Lyman series of hydrogen is λ\lambdaλ. The wavelength of the second member will beA275λ\frac{27}{5} \lambda527λB527λ\frac{5}{27} \lambda275λC2732λ\frac{27}{32} \lambda3227λD3227λ\frac{32}{27} \lambda2732λCheck answerSkip