MathematicsMedium202×since 2002Q5790If the vectors a→,b→\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}}a,b and c→\overrightarrow{\mathbf{c}}c from the sides BC,CAB C, C ABC,CA and ABA BAB respectively of a triangle ABCA B CABC, then :Aa→⋅b→=b→⋅c→=c→⋅b→=0\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}}=\overrightarrow{\mathbf{b}} \cdot \overrightarrow{\mathbf{c}}=\overrightarrow{\mathbf{c}} \cdot \overrightarrow{\mathbf{b}}=0a⋅b=b⋅c=c⋅b=0Ba→×b→=b→×c→=c→×a→\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}=\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}}=\overrightarrow{\mathbf{c}} \times \overrightarrow{\mathbf{a}}a×b=b×c=c×aCa→⋅b→=b→⋅c→=c→⋅a→=0\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}}=\overrightarrow{\mathbf{b}} \cdot \overrightarrow{\mathbf{c}}=\overrightarrow{\mathbf{c}} \cdot \overrightarrow{\mathbf{a}}=0a⋅b=b⋅c=c⋅a=0Da→×a→+a→×c→+c→×a→=0→\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{c}}+\overrightarrow{\mathbf{c}} \times \overrightarrow{\mathbf{a}}=\overrightarrow{\mathbf{0}}a×a+a×c+c×a=0Check answerSkip