MathematicsMedium64×since 2002Q2942If the 1011th 1011^{\text {th }}1011th term from the end in the binominal expansion of (4x5−52x)2022\left(\frac{4 x}{5}-\frac{5}{2 x}\right)^{2022}(54x−2x5)2022 is 1024 times 1011th 1011^{\text {th }}1011th R term from the beginning, then ∣x∣|x|∣x∣ is equal toA516\frac{5}{16}165B8C12D15Check answerSkip