MathematicsMedium178×since 2002Q5293If the sum of the first ten terms of the series (135)2+(225)2+(315)2+42+(445)2+.......is 165m,{\left( {1{3 \over 5}} \right)^2} + {\left( {2{2 \over 5}} \right)^2} + {\left( {3{1 \over 5}} \right)^2} + {4^2} + {\left( {4{4 \over 5}} \right)^2} + .......is\,{{16} \over 5}m,(153)2+(252)2+(351)2+42+(454)2+.......is516m, then m is equal to :A100B99C102D101Check answerSkip