MathematicsHard249×since 2002Q2499If the shortest distance between the straight lines 3(x−1)=6(y−2)=2(z−1)3(x - 1) = 6(y - 2) = 2(z - 1)3(x−1)=6(y−2)=2(z−1) and 4(x−2)=2(y−λ)=(z−3),λ∈R4(x - 2) = 2(y - \lambda ) = (z - 3),\lambda \in R4(x−2)=2(y−λ)=(z−3),λ∈R is 138{1 \over {\sqrt {38} }}381, then the integral value of λ\lambdaλ is equal to :A3B2C5D−-−1Check answerSkip