MathematicsMedium53×since 2002Q3227If the set {Re(z−zˉ+zzˉ2−3z+5zˉ):z∈C,Re(z)=3}\left\{\operatorname{Re}\left(\frac{z-\bar{z}+z \bar{z}}{2-3 z+5 \bar{z}}\right): z \in \mathbb{C}, \operatorname{Re}(z)=3\right\}{Re(2−3z+5zˉz−zˉ+zzˉ):z∈C,Re(z)=3} is equal to the interval (α,β](\alpha, \beta](α,β], then 24(β−α)24(\beta-\alpha)24(β−α) is equal to :A36B27C42D30Check answerSkip